Zipping a shapefile using python
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UPDATE:
After receiving a request to modify the code to ignore .lock files, I have an updated to this post.
One of the tasks I’ve been automating is publishing a weekly data update to a website. The update consists of shapefile. The trouble with shapefiles is they consist of 3 or more files with the same basename but different extensions in the same directory.
Not an overly complicated situation but a common one that ArcGIS does not have a solution out-of-the-box. Below is a bare-bones code snippet to do it. It has both the input shapefile and output zip file hard-coded. The call to the subroutine that does the work is: zipShapefile(wellsShapeFile,wellsZipFile)
import zipfile
import sys
import os
import glob
wellsShapeFile = "C:/cwi5_bk/WELLS/wells.SHP"
wellsZipFile = "C:/cwi5_bk/WELLS/test5.zip"
def zipShapefile(inShapefile, newZipFN):
print 'Starting to Zip '+inShapefile+' to '+newZipFN
if not (os.path.exists(inShapefile)):
print inShapefile + ' Does Not Exist'
return False
if (os.path.exists(newZipFN)):
print 'Deleting '+newZipFN
os.remove(newZipFN)
if (os.path.exists(newZipFN)):
print 'Unable to Delete'+newZipFN
return False
zipobj = zipfile.ZipFile(newZipFN,'w')
for infile in glob.glob( inShapefile.lower().replace(".shp",".*")):
print infile
zipobj.write(infile,os.path.basename(infile),zipfile.ZIP_DEFLATED)
zipobj.close()
return True
zipShapefile(wellsShapeFile,wellsZipFile)
print "done!"